Quando tendo listar os comandos do console php bin/console list estou recebendo a seguinte mensagem:An option named "connection" already exists.
Esse é o meu composer.json
` { "type": "project", "license": "proprietary", "require": { "php": "^7.1.3", "ext-ctype": "", "ext-iconv": "", "doctrine/doctrine-bundle": "^1.11", "doctrine/doctrine-fixtures-bundle": "3.1", "doctrine/doctrine-migrations-bundle": "^3.0", "doctrine/orm": "^2.7", "firebase/php-jwt": "^6.1", "laminas/laminas-zendframework-bridge": "^1.5", "sensio/framework-extra-bundle": "^5.2", "symfony/console": "4.2.", "symfony/dotenv": "4.2.", "symfony/flex": "^1.1", "symfony/framework-bundle": "4.2.", "symfony/maker-bundle": "^1.11", "symfony/proxy-manager-bridge": "4.2.", "symfony/security-bundle": "4.2.", "symfony/yaml": "4.2." }, "config": { "preferred-install": { "": "dist" }, "sort-packages": true, "allow-plugins": { "symfony/flex": true } }, "autoload": { "psr-4": { "App\": "src/" } }, "autoload-dev": { "psr-4": { "App\Tests\": "tests/" } }, "replace": { "paragonie/random_compat": "2.", "symfony/polyfill-ctype": "", "symfony/polyfill-iconv": "", "symfony/polyfill-php71": "", "symfony/polyfill-php70": "", "symfony/polyfill-php56": "" }, "scripts": { "auto-scripts": { "cache:clear": "symfony-cmd", "assets:install %PUBLIC_DIR%": "symfony-cmd" }, "post-install-cmd": [ "@auto-scripts" ], "post-update-cmd": [ "@auto-scripts" ] }, "conflict": { "symfony/symfony": "" }, "extra": { "symfony": { "allow-contrib": false, "require": "4.2.*" } } }
`
