No código abaixo:
package main
import "fmt"
func main() {
showMenu()
/*
"%d" means we expect an integer (go figure).
"&" means the variable address in memory, since Scanf does not expect a variable, but an address to one that already exists.
& in front of any var, does not return the var, but the address
fmt.Scanf("%d", &option)
*/
option := 0
fmt.Scan(&option) // fmt.Scan function (not Scanf) avoids passing the type expected for the input.
fmt.Println("You chose the option", option)
if option == 1 {
} else if option == 2 {
} else if option == 0 {
fmt.Println("Good bye.")
} else {
fmt.Println("Invalid option, will exit.")
return
}
}
func showMenu() {
fmt.Println("Welcome to this complex environment.")
fmt.Println("Please choose an option:.")
fmt.Println("1) Start monitoring")
fmt.Println("2) Show logs")
fmt.Println("0) Leave")
}O programa não está aguardando qualquer input de usuário, tendo como saída o seguinte:
$ go run main.go
Welcome to this complex environment.
Please choose an option:.
1) Start monitoring
2) Show logs
0) Leave
You chose the option 0
Good bye.Encontrei algo semelhante aqui (https://stackoverflow.com/questions/17401709/why-doesnt-fmt-scanf-in-go-wait-for-user-input), mas não me ajudou. Vocês já tiveram este problema antes?
